High School

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In wild turkeys, a dominant allele (B) produces familiar bronze-colored turkeys, and a recessive allele (b) produces a white color. Another dominant allele (N) produces normal feathers, and its recessive allele (n) produces strange hair-like feathers. A male turkey heterozygous for color with strange hair-like feathers mates with a female that is heterozygous for both traits.

Create a dihybrid Punnett square and determine the outcomes:

a) No feathers are produced

b) All bronze-colored turkeys

c) All white turkeys

d) Some bronze-colored and some white turkeys

Answer :

Final answer:

When a male turkey heterozygous for bronze color and with strange hair-like feathers mates with a female heterozygous for both traits, their offspring will include some bronze-colored and some white turkeys with combinations of normal and strange hair-like feathers.

Explanation:

In wild turkeys, the coexistence of a dominant allele for the bronze color (B) and a recessive allele for the white color (b), as well as a dominant allele for normal feathers (N) and a recessive allele for strange hair-like feathers (n), allows for a variety of genotypes and phenotypes. To answer the student's question, we need to set up a dihybrid Punnett square. The male turkey is heterozygous for color (Bb) and has strange hair-like feathers (nn), while the female is heterozygous for both traits (BbNn).

The possible genotypes of their offspring can be predicted by a dihybrid Punnett square:

  • BBNN, BBnN, BbNN, BbnN (bronze-colored with normal feathers)
  • BBnn, Bbnn (bronze-colored with strange hair-like feathers)
  • bb, bbnN (white with normal feathers)
  • BBN (white with strange hair-like feathers)

Therefore, the correct answer to the student's question is d) Some bronze-colored and some white turkeys will be produced as a result of the mating between the two turkeys described.

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