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Answer :
Final answer:
The half-life of a zeroth-order reaction can be calculated using the formula t1/2 = [A]0 / (2k), where [A]0 is the initial concentration of reactant and k is the rate constant. Substituting the given values yields a half-life of 3.21 × 10-8 s.
Explanation:
The half-life of a reaction is the time required for one-half of a given amount of reactant to be consumed. In zeroth-order reactions, the half-life is dependent on the initial concentration of the reactant. The formula for calculating the half-life of a zeroth-order reaction is given by:
t1/2 = [A]0 / (2k)
Where [A]0 is the initial concentration of reactant and k is the rate constant. In this case, the rate constant is given as 36.6 M. Therefore, the half-life of the reaction is:
t1/2 = (2.35 × 10-6 M) / (2 * 36.6 M) = 3.21 × 10-8 s
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