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Answer :
Final answer:
The Energy Loss when 0.112 kg of iron cools from 118 °C to 55.1 °C is 757.6 Calories, which is equivalent to 3170 Joules.
Explanation:
The energy loss of an object can be determined using the formula: q = mcΔT, where q is the energy transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
The mass should be in grams, so 0.112 kg becomes 112 g. The temperature change, ΔT is (55.1°C - 118°C) = -62.9°C. However, we drop the negative sign because energy loss is always considered as positive. Therefore, we substitute these values in the formula and get: q = 112g x 0.108 cal/g°C x 62.9°C = 757.6 Calories.
The conversion from Calories to joules is 1 Calorie = 4.184 Joules. Therefore, 757.6 Calories = 3170 Joules.
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