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Answer :
Final answer:
The pOH of a solution with a pH of 6.25 and a Kw of 5.6 x 10⁻¹³ at 100 degrees Celsius is 6.00. This is because the sum of pH and pOH equals pKw, which is the negative logarithm of Kw.
Explanation:
The relationship between pH, pOH, and Kw in water can be expressed by the equation pH + pOH = pKw. Given that the pH is 6.25 and the Kw of water at 100 degrees Celsius is 5.6 x 10^-13, we can solve for pOH.
Firstly, we calculate pKw by taking the negative logarithm of Kw, which is -log(5.6×10⁻¹³) = 12.25. If we plug these values into the equation, we get 6.25 + pOH = 12.25.
By solving for pOH, we can see that the pOH would be 12.25 - 6.25 = 6.00,
so the correct answer is 6.00.
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