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Answer :
Final answer:
The force F applied to the handle is approximately 105.04 N.
Explanation:
To find the force F applied to the handle, we need to resolve the forces acting on the suitcase. The normal force is equal to the weight, which in this case is the mass (23 kg) multiplied by the gravitational acceleration (9.8 m/s²). So, the normal force is 23 kg * 9.8 m/s² = 225.4 N.
The force F is the component of the applied force that is perpendicular to the plane of motion. It can be found by using the formula F = Fnormal * tan(angle), where angle is 25°. So, F = 225.4 N * tan(25°) = 225.4 N * 0.466 = 105.04 N.
Therefore, the force F applied to the handle is approximately 105.04 N.
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