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Answer :
Final answer:
The stall speed in knots equivalent airspeed (KEAS) for aircraft, given the condition Weight = 20,000 lbs, Sea level and Wing area = 200 ft2 CLmax = 1.5 by using the formula Vs=sqrt((2*W) / (ρ*Area*CLmax)). So, the answer is 135 KTAS.
Explanation:
The stall speed in knots equivalent airspeed (KEAS) for aircraft.
By using the formula:
[tex]Vs=sqrt((2*W) / (ρ*Area*CLmax)).[/tex]
Where Vs is the stall speed,
W is the weight of the aircraft,ρ is the air density
A is the wing area and CL is the coefficient of lift.
Substituting the given values for this aircraft
Weight = 20,000 lbs,
A= (200 ft²),
ρ approximates 0.002377 slugs/ft³ at sea level, and
CLmax = 1.5,
we get:
VS=sqrt ((2*20,000)/(0.002378*200*1.5)).
Calculating this equation gives a VS of approximately 135 KEAS,
Therefore, the answer is 135 KTAS.
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