High School

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Josiah invests [tex] \$360 [/tex] into an account that accrues [tex] 3\% [/tex] interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah's account, [tex] y [/tex], after [tex] x [/tex] years?

A. [tex] y = 360(1.3)^x [/tex]
B. [tex] y = 360(0.3)^x [/tex]
C. [tex] y = 360(0.03)^x [/tex]
D. [tex] y = 360(1.03)^x [/tex]

Answer :

To solve the problem of determining which equation represents the amount of money in Josiah's account after [tex]$x$[/tex] years, we need to use the concept of compound interest.

Josiah's investment grows with compound interest, where the formula is:

[tex]\[ y = P \times (1 + r)^x \][/tex]

where:
- [tex]\( P \)[/tex] is the principal amount (initial investment),
- [tex]\( r \)[/tex] is the annual interest rate (expressed as a decimal),
- [tex]\( x \)[/tex] is the number of years the money is invested.

In this question:
- The principal amount [tex]\( P \)[/tex] is \$360.
- The annual interest rate [tex]\( r \)[/tex] is 3%, which as a decimal is 0.03.
- The number of years is represented by [tex]\( x \)[/tex].

So, substituting these values into the compound interest formula, we get:

[tex]\[ y = 360 \times (1 + 0.03)^x \][/tex]
[tex]\[ y = 360 \times (1.03)^x \][/tex]

Therefore, the equation that represents the amount of money in Josiah's account after [tex]\( x \)[/tex] years is:

[tex]\[ y = 360 \times (1.03)^x \][/tex]

Among the given options, this matches the fourth equation:

[tex]\[ y = 360(1.03)^x \][/tex]

This is the correct choice.

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