High School

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Practice proving that a quadrilateral is a parallelogram.

In quadrilateral [tex]WXYZ[/tex], [tex]WC = 2x + 5[/tex] and [tex]CY = 3x + 2[/tex]. What must [tex]x[/tex] equal for quadrilateral [tex]WXYZ[/tex] to be a parallelogram?

[tex]x = \square[/tex]

Answer :

To determine the value of [tex]\( x \)[/tex] for quadrilateral [tex]\( WXYZ \)[/tex] to be a parallelogram, we need to understand that in a parallelogram, opposite sides are equal.

In quadrilateral [tex]\( WXYZ \)[/tex], we have:
- [tex]\( WZ = 2x + 5 \)[/tex]
- [tex]\( CY = 3x + 2 \)[/tex]

For [tex]\( WXYZ \)[/tex] to be a parallelogram, the opposite sides [tex]\( WZ \)[/tex] and [tex]\( CY \)[/tex] must be equal. Therefore, we set up the equation:

[tex]\[ 2x + 5 = 3x + 2 \][/tex]

Now, let's solve this equation for [tex]\( x \)[/tex]:

1. Subtract [tex]\( 2x \)[/tex] from both sides of the equation to get:

[tex]\[ 5 = x + 2 \][/tex]

2. Next, subtract 2 from both sides to find the value of [tex]\( x \)[/tex]:

[tex]\[ 5 - 2 = x \][/tex]

[tex]\[ x = 3 \][/tex]

Thus, the value of [tex]\( x \)[/tex] that makes quadrilateral [tex]\( WXYZ \)[/tex] a parallelogram is [tex]\( x = 3 \)[/tex].

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