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A 27.0 cm long spring is hung vertically from a ceiling and stretches to 32.9 cm when an 8.50 kg mass is hung from its free end.

1. Find the spring constant.
2. Find the length of the spring (in cm) if the 8.50 kg weight is replaced with a 215 N weight.

Answer :

Final answer:

The spring constant can be calculated using Hooke's law. The spring constant is approximately 43 N/cm. The length of the spring when a 215 N weight is attached is approximately 5 cm.

Explanation:

The spring constant, also known as the force constant or stiffness, can be calculated using Hooke's law. Hooke's law states that the force exerted by a spring is proportional to the displacement from its equilibrium position. In this case, the spring constant can be found by dividing the weight of the 8.50 kg mass by the displacement of the spring: k = F / x

Substituting the values into the equation, we get: k = 215 N / (32.9 cm - 27.0 cm). Solving the equation, the spring constant is found to be approximately 43 N/cm. To find the length of the spring when a 215 N weight is attached, we can use Hooke's law again: F = kx. Substituting the values into the equation, we get: (215 N) = (43 N/cm) x. Solving for x, the length of the spring is approximately 5 cm.

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