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Answer :
Answer:
The speed of Train #940 is 68.[tex]\overline{571458}[/tex] mph
Step-by-step explanation:
The given parameters of the w=question are;
The time at which train #941 leaves the station = 7 a.m.
The speed with which train #941 travels, v = 48 mph
The time at which train #940 leaves the station = 3 hours after train #941
Therefore;
The time at which train #940 leaves the station = 3 hours + 7 a.m. = 10 a. m.
The direction of train #940 = The direction of train #941
The time at which train #940 catches train #941 = 5 p.m.
We have;
The time, 't', (after departure of train #941) it takes train #940 to catch train #941, is given as follows;
t = 5 p.m. - 7 a.m.
∴ t = 17:00 hours - 07:00 hours = 10 hours
The time (after departure of train #941) it takes train #940 to catch train #941, t = 10 hours
The distance from St. Mark's Train Station train #940 catches Train #941, 'd', is given as follows;
d = The speed of travel of train #941 × t
∴ d = 48 mph × 10 h = 480 miles
The distance from St. Mark's Train Station train #940 catches Train #941, d = 480 miles
The time train
The time, t₂, it takes Train #940 to catch up with train #941 is given as follows;
t₂ = 5 p.m. - 10 a.m. = 17:00 hours - 10:00 hours = 7 hours
The speed of Train #940, v₂ = d/t₂
∴ v₂ = (480 miles)/(7 hours) = 68.[tex]\overline{571458}[/tex] mph
The speed of Train #940, v₂ = 68.[tex]\overline{571458}[/tex] mph
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