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When a projectile travels at 3000 feet per second, how far will it travel in meters if it travels for 18 minutes?

(Note: 1 meter = 3.28 feet)

Answer :

Final answer:

When a projectile travels at a speed of 3000 feet per second, it will cover approximately 988,000 meters in a span of 18 minutes.

Explanation:

To find out how far a projectile will travel in meters when it travels at 3000 feet per second for 18 minutes, we first need to convert time from minutes to seconds. So, 18 minutes is equal to 18 * 60 = 1080 seconds. Now, we can use the concept that distance traveled is speed multiplied by time. Here, speed is provided in feet per second so first we will find the distance in feet: it would be 3000(ft/s) * 1080(s) = 3,240,000 feet.

Now, we have the distance in feet, but we want the answer in meters. As given, 1 m = 3.28 ft, so to convert feet into meters, we have to divide the distance covered in feet by 3.28. Therefore, 3,240,000 feet / 3.28 = approx. 988,000 meters. Thus, the projectile will travel approximately 988,000 meters in 18 minutes when traveling at a speed of 3000 feet per second.

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