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Answer :
Let's go through Penny's solution step-by-step to see if she solved the equation correctly:
1. Original Equation:
[tex]\[
\frac{3}{5}y - 8 = 4
\][/tex]
This is the equation Penny started with.
2. Step 1: Isolate the Term with [tex]\(y\)[/tex]:
To solve for [tex]\(y\)[/tex], first add 8 to both sides to move the constant term to the right side:
[tex]\[
\frac{3}{5}y - 8 + 8 = 4 + 8
\][/tex]
Simplifying this gives:
[tex]\[
\frac{3}{5}y = 12
\][/tex]
3. Step 2: Solve for [tex]\(y\)[/tex]:
Next, multiply both sides of the equation by the reciprocal of [tex]\(\frac{3}{5}\)[/tex], which is [tex]\(\frac{5}{3}\)[/tex]:
[tex]\[
\left(\frac{5}{3}\right) \cdot \frac{3}{5}y = 12 \cdot \frac{5}{3}
\][/tex]
This simplifies the left side to [tex]\(y\)[/tex] because [tex]\(\frac{5}{3} \times \frac{3}{5} = 1\)[/tex]:
[tex]\[
y = 12 \cdot \frac{5}{3}
\][/tex]
Now, calculate the right side:
[tex]\[
y = \frac{60}{3}
\][/tex]
Simplifying the division gives:
[tex]\[
y = 20
\][/tex]
4. Conclusion:
Yes, Penny correctly solved for [tex]\(y\)[/tex]. The solution [tex]\(y = 20\)[/tex] is indeed correct.
1. Original Equation:
[tex]\[
\frac{3}{5}y - 8 = 4
\][/tex]
This is the equation Penny started with.
2. Step 1: Isolate the Term with [tex]\(y\)[/tex]:
To solve for [tex]\(y\)[/tex], first add 8 to both sides to move the constant term to the right side:
[tex]\[
\frac{3}{5}y - 8 + 8 = 4 + 8
\][/tex]
Simplifying this gives:
[tex]\[
\frac{3}{5}y = 12
\][/tex]
3. Step 2: Solve for [tex]\(y\)[/tex]:
Next, multiply both sides of the equation by the reciprocal of [tex]\(\frac{3}{5}\)[/tex], which is [tex]\(\frac{5}{3}\)[/tex]:
[tex]\[
\left(\frac{5}{3}\right) \cdot \frac{3}{5}y = 12 \cdot \frac{5}{3}
\][/tex]
This simplifies the left side to [tex]\(y\)[/tex] because [tex]\(\frac{5}{3} \times \frac{3}{5} = 1\)[/tex]:
[tex]\[
y = 12 \cdot \frac{5}{3}
\][/tex]
Now, calculate the right side:
[tex]\[
y = \frac{60}{3}
\][/tex]
Simplifying the division gives:
[tex]\[
y = 20
\][/tex]
4. Conclusion:
Yes, Penny correctly solved for [tex]\(y\)[/tex]. The solution [tex]\(y = 20\)[/tex] is indeed correct.
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