128 N of force is applied to a 64 kg block, accelerating it at 2 m/s². A second 60 kg object is also accelerating at 2 m/s². How does the force applied to the two blocks compare?

Question

High School

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Answer :

OliviaLunaGracy OliviaLunaGracy · Answer 1 · 2023-11-13T02:48:57-05:00

To understand how the forces applied to the two blocks compare, we can use Newton's second law of motion, which is stated as:

[tex]F = ma[/tex]

where:

[tex]F[/tex] is the force applied (in newtons, N),
[tex]m[/tex] is the mass of the object (in kilograms, kg),
[tex]a[/tex] is the acceleration of the object (in meters per second squared, m/s²).

For the first block:

We can calculate the required force [tex]F_1[/tex] using the formula:

[tex]F_1 = m_1 \times a = 64 \text{ kg} \times 2 \text{ m/s}^2 = 128 \text{ N}[/tex]

This matches the force given as 128 N applied to accelerate the block.

For the second block:

We calculate the force [tex]F_2[/tex] using the same formula:

[tex]F_2 = m_2 \times a = 60 \text{ kg} \times 2 \text{ m/s}^2 = 120 \text{ N}[/tex]

Comparison of Forces:

Thus, the force applied to the first block is greater than the force applied to the second block by 8 N.