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An electric force of [tex]7.19 \times 10^{-8} \, \text{N}[/tex] acts between two charges, both of magnitude [tex]2.00 \times 10^{-10} \, \text{C}[/tex].

Calculate the distance between the two charges.

Answer :

Final answer:

To determine the distance between the two charges, one must use Coulomb's Law, which is 'F = k.q1.q2 / r^2'. Then rearrange and insert the given details into the equation to solve for 'r', which turns out to be around 0.084 m or 8.4 cm.

Explanation:

To find the distance between the two charges, we should employ Coulomb's Law. ˣF = k.q1.q2 / r²ˣ

where:

F is the electric force = 7.19 x 10⁻⁸ N

k is Coulomb's constant = 8.99 x 10⁹ N.m²/C²

q1, q2 are the magnitudes of the two charges = 2.00 x 10⁻¹⁰ C

r is the distance between the two charges which we are solving for.

Isolating r, we have:

r = sqrt[ (k.q1.q2) / F ]

Substituting the given values, we obtain:

r = sqrt [ (8.99 x 10⁹ N.m²/C² ˣ (2.00 x 10⁻¹⁰ C)²) / 7.19 x 10⁻⁸ N ]

Thus,ˣˣr ≈ 0.084 cmˣˣ or ˣˣ8.4 cmˣˣ.

Learn more about Coulomb's Law

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