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Answer :
The work required to lift a 215 kg mass a distance of 5.75 m using a machine that is 72.5% efficient is 16,430 Joules.
This is calculated by first finding the work output of the machine, which is 11,918.625 Joules, and then dividing it by the efficiency factor. The work required is 16,430 Joules. The direct answer involves calculating the work output of the machine (11,918.625 Joules) and dividing it by the efficiency factor (0.725) to determine the work input. The summary emphasizes the final answer and highlights the calculation steps involving the work output, efficiency, and work input.
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