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An airplane has a mass of 94,000 kg. What is the minimum necessary lift force to get the airplane off the ground? Assume the acceleration due to gravity is [tex]10 \, \text{m/s}^2[/tex].

Answer :

The minimum necessary lift force to get a 94000 kg airplane off the ground is 940000 N, calculated by multiplying the mass by the acceleration due to gravity[tex](10 m/s^2).[/tex]

The minimum necessary lift force to get the airplane off the ground must equal the gravitational force acting on the airplane. This force can be calculated using the formula F = m imes g, where F is the force due to gravity (also known as weight), m is the mass of the airplane, and g is the acceleration due to gravity. Given that the airplane has a mass of 94000 kg and the acceleration due to gravity is approximated to 10 m/s2, the minimum necessary lift force is:

F = m imes g = 94000 kg imes 10 m/s2 = 940000 N (Newtons)

Therefore, the minimum necessary lift force required for the airplane to take off is 940000 N.

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