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You arrive home to find that your 25-foot by 40-foot basement has 18 inches of water in it.

a) If 1 cubic foot of water is about 7.48 gallons, how much water will you be pumping out of your basement? Express your answer rounded to the nearest tenth of a gallon.

b) If you have a pump that can pump 700 gallons of water per hour, how long will it take to empty the basement? Express your answer rounded to the nearest tenth of an hour.

Answer :

a) You will be pumping out approximately 11,220 gallons of water from your basement.

b) It will take approximately 16 hours to empty the basement with a pump that can handle 700 gallons of water per hour.

a) To calculate the amount of water you will be pumping out of your basement, we need to determine the volume of water in cubic feet and then convert it to gallons.

The basement dimensions are 25 feet by 40 feet, and the water level is 18 inches. To calculate the volume of water in cubic feet, we multiply the area of the basement (25 ft * 40 ft) by the height of the water (18/12 ft):

Volume = (25 ft * 40 ft * 18/12 ft) = 1500 ft³

Now, to convert cubic feet to gallons, we multiply the volume by the conversion factor of 7.48 gallons per cubic foot:

Water in gallons = 1500 ft³ * 7.48 gallons/ft³ ≈ 11,220 gallons

Therefore, you will be pumping out approximately 11,220 gallons of water from your basement.

b) If your pump can handle 700 gallons of water per hour, we can calculate the time it will take to empty the basement by dividing the total volume of water by the pumping rate:

Time = Water in gallons / Pumping rate

Time = 11,220 gallons / 700 gallons per hour ≈ 16 hours

Therefore, it will take approximately 16 hours to empty the basement with a pump that can handle 700 gallons of water per hour.

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