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Answer :
I will use the binomial distrubion to find the probability.
[tex] \displaystyle
P(A)=\binom{n}{k}p^k(1-p)^{n-k} [/tex]
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A - selecting a red checker exactly 7 times in 10 selections
[tex] n=7\\
k=10 [/tex]
[tex] \displaystyle
P(A)=\binom{10}{7}\cdot\left(\dfrac{12}{15}\right)^7\cdot\left(1-\dfrac{12}{15}\right)^{10-7}\\\\
P(A)=\dfrac{10!}{7!3!}\cdot\left(\dfrac{4}{5}\right)^7\cdot\left(1-\dfrac{4}{5}\right)^3\\\\
P(A)=\dfrac{8\cdot9\cdot10}{2\cdot3}\cdot\dfrac{16384}{78125}\cdot\left(\dfrac{1}{5}\right)^3\\\\
P(A)=120\cdot\dfrac{16384}{78125}\cdot\dfrac{1}{125}\\\\
P(A)=\dfrac{393216}{1953125}\approx0.2=20\%[/tex]
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