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Answer :
Using the 68-95-99.7 rule for the normal distribution, approximately 16% of students score above 600 on the standardized test.
The question asks for the percentage of students scoring above 600 on a standardized test given a normal distribution with a mean of 500 and a standard deviation of 100. Using the 68-95-99.7 rule, we know that approximately 95% of scores fall within two standard deviations of the mean. Since 600 is one standard deviation above the mean, this corresponds to the 84th percentile. Therefore, 100% - 84% = 16% of students score above 600.
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