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Answer :
There are 15 ways she can choose the fruits. Since order is not important, this is a combination.
The combination is given by
[tex]_6C_2=\frac{6!}{2!4!}=\frac{720}{48}=15[/tex]
The combination is given by
[tex]_6C_2=\frac{6!}{2!4!}=\frac{720}{48}=15[/tex]
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Rewritten by : Barada
The order doesn't matter. It's the combination then.
[tex]k [/tex] objects can be chosen out of [tex] n [/tex] objects, when the order doesn't matter, in [tex] C(n,k)=\dfrac{n!}{k!(n-k)!} [/tex] ways.
So, the answer is [tex] C(6,2)=\dfrac{6!}{2!4!}=\dfrac{5\cdot6}{2}=15 [/tex] ways.
