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Answer :
Answer:
Width = 10 in
Length = 50 in
Step-by-step explanation:
Define the variables
- Let x be the width of the rectangle.
- If the length is five times its width, then the length of the rectangle is 5x.
Given the perimeter is 120 in:
[tex]\begin{aligned}\textsf{Perimeter of a rectangle} & = 2(\sf width + length)\\120 & = 2(x + 5x)\\120 & = 2(6x)\\120 & = 12x\\\dfrac{12x}{12}&=\dfrac{120}{12}\\\implies x&=10\end{aligned}[/tex]
Solution:
- Width = 10 in
- Length = 5 × 10 in = 50 in
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