Answer :

The boy's power output is 196 W, making the correct answer choice "d. 196 W". The power output of the 40-kg boy climbing the vertical ladder at 0.5 m/s can be calculated using the formula P = mgh/t, where P is power, m is mass, g is acceleration due to gravity, h is height, and t is time.

Since the ladder is vertical, we can assume that the height climbed is equal to the distance covered, which is given by speed × time. Therefore, the height climbed in three seconds would be 0.5 m/s × 3 s = 1.5 m.
Using the formula, we get: P = (40 kg) × (9.8 m/s²) × (1.5 m) / (3 s) = 196 W. Therefore, the answer is (d) 196 W.
The power output of the boy can be calculated using the formula: Power (P) = Force (F) × Velocity (V). In this case, we need to determine the force first, which can be found using the equation: Force (F) = Mass (m) × Acceleration due to gravity (g). Given the mass of the boy as 40 kg and the acceleration due to gravity as 9.81 m/s², we can calculate the force: F = 40 kg × 9.81 m/s² = 392 N. Now, we can find the power output using the given velocity of 0.5 m/s: P = 392 N × 0.5 m/s = 196 W.

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