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A student combined 37.2 mL of a 1.69 M KMnO₄ solution with 17.40 mL of a 0.891 M KMnO₄ solution. Calculate the concentration of the final solution.

Answer :

Final answer:

The concentration of the final solution is 1.437 M.

Explanation:

To calculate the concentration of the final solution, we can use the formula:

C₁V₁ + C₂V₂ = C₃V₃

where C₁ and V₁ are the concentration and volume of the first solution, C₂ and V₂ are the concentration and volume of the second solution, and C₃ and V₃ are the concentration and volume of the final solution.

In this case, we have the following values:

Substituting these values into the formula, we get:

(1.69 M)(37.2 ml) + (0.891 M)(17.40 ml) = C₃V₃

Simplifying the equation:

63.108 M·ml + 15.3984 M·ml = C₃V₃

78.5064 M·ml = C₃V₃

Since we are calculating the concentration of the final solution, we can assume that the volume of the final solution is the sum of the volumes of the two solutions:

V₃ = V₁ + V₂ = 37.2 ml + 17.40 ml = 54.60 ml

Substituting this value into the equation:

78.5064 M·ml = C₃(54.60 ml)

Solving for C₃:

C₃ = 78.5064 M·ml / 54.60 ml = 1.437 M

Therefore, the concentration of the final solution is 1.437 M.

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