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A sequence starts at 112 and subtracts 6 repeatedly. What are the first four terms?

A. 112, 106, 100, 94
B. 106, 112, 118, 124
C. 106, 100, 94, 88
D. 112, 118, 124, 130

Answer :

Final Answer:

The first four terms of the sequence are 112, 106, 100, 94. Option A is answer.

Explanation:

The sequence starts at 112 and subtracts 6 repeatedly to generate the subsequent terms. So, to find each term, you subtract 6 from the previous one:

1st term: 112

2nd term: 112 - 6 = 106

3rd term: 106 - 6 = 100

4th term: 100 - 6 = 94

Therefore, the first four terms of the sequence are 112, 106, 100, and 94, which corresponds to option A.

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