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Self-paced Calculus 1-Fall 2021 Homework: 2.2 unit 1 (a) It can be shown that the inequalities 1- 2 (b) Graph 1-2-2 coax andy1 together for-25x52. Comment on the behavior of the (a) Choose the correct answer below Gái t does not FOB. m 1-lm 1- 0 OF xinx 2-2005- 0 2-200x xnx 2-2005 Obecause m ist because im 1-7 1 Question 25, 2.2.65 Part 1 of 3 sains 1 hold for all values of a close to zero. What, if anything, does this tell you about tim -2 cox 40 Soña Valiani 06/02/22 9:24 PM HW Score: 81.51%, 21.19 of 26 points O Points: 0 of 1 7 Give reasons for your answer sinx 2-2000x

Answer :

In this problem, we are given the inequality 1 - 2|a| ≤ 0. We need to determine if this inequality holds for all values of a close to zero and discuss what this tells us about the behavior of the function sin(x) - 2x.

The given inequality is 1 - 2|a| ≤ 0. To analyze the behavior of this inequality as a approaches zero, we consider two cases: a > 0 and a < 0.

Case a > 0:

In this case, the inequality becomes 1 - 2a ≤ 0. Solving for a, we get a ≤ 1/2. As a approaches zero from the positive side, a ≤ 1/2 still holds true.

Case a < 0:

In this case, the inequality becomes 1 + 2a ≤ 0. Solving for a, we get a ≤ -1/2. As a approaches zero from the negative side, a ≤ -1/2 still holds true.

Therefore, for all values of a close to zero, the inequality 1 - 2|a| ≤ 0 holds true.

Now, considering the behavior of the function f(x) = sin(x) - 2x, we can conclude that as x approaches zero, the function approaches zero or remains bounded.

This is because the inequality holds for all values of a close to zero, indicating that the function sin(x) - 2x does not cross the x-axis near x = 0.

In summary, the given inequality 1 - 2|a| ≤ 0 holds for all values of a close to zero, which tells us that the function sin(x) - 2x does not cross the x-axis near x = 0.

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