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Answer :
The range of acceptable values for the 16-oz boxes of cereal with a discrepancy tolerance is (c) 15.85 oz to 16.15 oz.
To determine the range of acceptable values for the boxes of cereal weighing 16 oz with a tolerance of [tex]\pm\ 0.15\ oz[/tex], we need to find the minimum and maximum acceptable weights.
The acceptable weight range can be calculated as follows:
Minimum weight = [tex]16 \ oz - 0.15\ oz = 15.85\ oz[/tex]
Maximum weight = [tex]16\ oz + 0.15\ oz = 16.15\ oz[/tex]
Complete question:
A company manufactures 16-oz boxes of cereal. Boxes are randomly weighted to ensure the correct amount. If the discrepancy in weight is more than 0.15 oz, the production is stopped. What is the range of acceptable values for production to continue?
(a) 15.15 oz to 16.00 oz
(b) 15.85 oz to 16.00 oz
(c) 15.85 oz to 16.15 oz
(d) 16.15 oz to 16.45 oz
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Rewritten by : Barada
The range of acceptable values for production to continue working of the company without stoppage is 15.85 to 16.15.
What is the range of acceptable values?
Range is the area of fluctuation between the upper and lower limit. The range of the acceptable values is all the values between the upper and lower limit.
Here, a company manufactures 16-oz boxes of cereal. Now, this boxes are randomly weighted to ensure the correct amount.
As the discrepancy in weight is more than 0.15 oz then the production of the company is stopped.
To proper functioning of the company without stoppage, the limit of the production should be with in 0.15 oz.
The company produce, 16-oz boxes of cereal and the disperancy is 0.15 oz. Thus the value of the lower limit will be,
[tex]L=16-0.15\\L=15.85\rm \; oz[/tex]
The value of the upper limit will be,
[tex]U=16+0.15\\U=16.15\rm \; oz[/tex]
Thus, the range will be {15.85-16.15 oz}
Hence, the range of acceptable values for production to continue working of the company without stoppage is 15.85 to 16.15.
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