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Answer :
Answer: The mass of water reacted is 36 grams
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the reaction of sulfur dioxide with bromine and water follows:
[tex]SO_2+Br_2+2H_2O\rightarrow 2HBr+H_2SO_4[/tex]
Let the mass of water be 'x' grams
We are given:
Mass of sulfur dioxide = 64.1 grams
Mass of bromine = 159.9 grams
Mass of hydrogen bromide = 161.9 grams
Mass of sulfuric acid = 98.1 grams
Total mass on reactant side = 64.1 + 159.9 + x = 224 + x
Total mass on product side = 161.9 + 98.1 = 260 g
So, by applying law of conservation of mass, we get:
[tex]224+x=260\\\\x=(260-224)=36g[/tex]
Hence, the mass of water reacted is 36 grams.
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Answer:
The answer to your question is:
a) 36 g of water
Explanation:
MW SO₂ = 32 + 32 = 64 g
MW Br = 80 g
MW H₂O = 18 g
MW HBr = 81 g
MW H₂SO₄ = 98
Balanced reaction:
SO₂ + 2Br + 2H₂O ⇒ 2HBr + H₂SO₄
64g 2(80) 2(18) 2(81) 98
64.1 159.9 161.9 98.1
Rule of three with Br and H2O
160 g ---------------- 36 g
160 ------------------- x
x = 160(36)/160 = 36 g oh water
