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Answer :
Final answer:
To fully neutralize 1.69 moles of acetic acid (HC₂H₃O₂), exactly 1.69 moles of calcium hydroxide (Ca(OH)₂) is required. The correct answer is a. 1.69 moles.
Explanation:
The question is asking how many moles of calcium hydroxide (Ca(OH)₂) would be needed to completely neutralize 1.69 moles of acetic acid (HC₂H₃O₂). This involves a stoichiometry problem in which the balanced chemical equation dictates the relationship between the reactants. The reaction is a double-replacement reaction that is neutralization, and it is balanced as: HC₂H₃O₂ + Ca(OH)₂ -> Ca(C₂H₃O₂)₂ + 2H₂O From this balanced equation, we can see that 1 mole of acetic acid will react with 1 mole of calcium hydroxide. Therefore, to neutralize 1.69 moles of acetic acid, we will require 1.69 moles of calcium hydroxide. Therefore option a. 1.69 moles is the correct answer.
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