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A 0.50 kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it is 235 N. If the ball's speed after being struck is 3.1 m/s, how long was the duration of the force?

Answer :

Final answer:

To find the duration of the force exerted on the croquet ball, we can use the concept of impulse. The impulse experienced by an object is equal to its change in momentum. Therefore, we can calculate the duration of the force by finding the time interval over which the impulse occurs.

Explanation:

To find the duration of the force exerted on the croquet ball, we can use the concept of impulse. Impulse is defined as the product of the average force exerted on an object and the time interval over which the force is exerted. The impulse experienced by an object is equal to its change in momentum.

Using the formula for impulse, we can calculate the duration of the force exerted on the croquet ball as follows:

Impulse = Force * Time

Momentum = Mass * Velocity

Since the ball is initially at rest, its initial momentum is zero. After being struck, the ball's speed is 3.1 m/s. We can plug these values into the equation to solve for the duration of the force:

Momentum = Mass * Velocity

0.5 kg * 3.1 m/s = 235 N * Time

Time = (0.5 kg * 3.1 m/s) / 235 N

Time = 0.00638 s

Therefore, the duration of the force exerted on the croquet ball is approximately 0.00638 seconds.

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