High School

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An elevator has a placard stating that the maximum capacity is 3900 lb for 26 passengers. This means 26 adult male passengers can have a mean weight of up to [tex]\frac{3900}{26} = 150[/tex] pounds. Assume that weights of males are normally distributed with a mean of 186 lb and a standard deviation of 40 lb.

Find the probability that 1 randomly selected adult male has a weight greater than 150 lb.

Answer :

Final answer:

The probability that 1 randomly selected adult male weighs more than 150 lb, with the given normal distribution (mean of 186 lb, standard deviation of 40 lb), is approximately 81.59%.

Explanation:

The student asks to find the probability that 1 randomly selected adult male has a weight greater than 150 lb, given that weights of males are normally distributed with a mean of 186 lb and a standard deviation of 40 lb. To calculate this, we can use the Z-score formula:

Z = (X - μ) / σ

where X is the value of interest (150 lb), μ is the mean (186 lb), and σ is the standard deviation (40 lb).

Substituting the values into the formula, we get:

Z = (150 - 186) / 40 = -0.9

We then look up this Z-score in a standard normal distribution table, or use a calculator with a normal distribution function, to find the probability that a value is above this Z-score. The probability associated with Z = -0.9 is approximately 0.8159.

Therefore, the probability that a randomly selected male weighs more than 150 pounds is about 81.59%.

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