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DL and BM are the heights on sides AB and AD, respectively, of parallelogram ABCD. If the area of the parallelogram is [tex]1470 \text{ cm}^2[/tex], AB = 35 cm, and AD = 49 cm, find the lengths of BM and DL.

Answer :

Final answer:

To find the lengths of heights BM and DL in the parallelogram, we divide the area of the parallelogram by the lengths of their corresponding bases. Thus, BM equals 30 cm and DL equals 42 cm.

Explanation:

The question asks to find the lengths of the heights BM and DL in a parallelogram ABCD given the lengths of sides AB and AD, and the area of the parallelogram. In any parallelogram, the area can be calculated as the base multiplied by the height (Area = base × height). Since the area of the parallelogram is given as 1470 cm2, and we have the lengths of the bases (AB=35cm and AD=49cm), we can find the heights.

To find BM (the height corresponding to base AD), we use the formula:
Area = AD × BM, giving us BM = Area / AD = 1470 / 49 = 30 cm.

Similarly, to find DL (the height corresponding to base AB), we use the formula:
Area = AB × DL, giving us DL = Area / AB = 1470 / 35 = 42 cm.

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Rewritten by : Barada

Answer:

BM = 30 cm, DL = 42 cm

Step-by-step explanation:

The area of the parallelogram = 1470 cm², AB = 35 cm, AD = 49 cm, DL and BM are the heights on sides AB and AD.

area of the parallelogram = base × height = AD × height of AD = AD × BM

⇒ 1470 cm² = 49 cm × BM

BM = 1470 cm² / 49 cm = 30 cm

BM = 30 cm

Also:

area of the parallelogram = base × height = AB × height of AB = AB × DL

⇒ 1470 cm² = 35 cm × DL

DL = 1470 cm² / 35 cm = 42 cm

DL = 42 cm