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Answer :
Final answer:
From the given mass of NaNO3 and volume of the solution, we can find the molarity of the NaNO3 solution to be approximately 0.154 M.
Explanation:
The molarity of a solution is calculated by the formula: Molarity (M) = moles of solute / liters of solution. First, we need to convert the mass of NaNO3 into moles. The molar mass of NaNO3 is approximately 85 g/mol. So, 39.3 g of NaNO3 is (39.3 g / 85 g/mol) = approximately 0.462 moles. The volume of the solution is 3.00 L. Hence, the molarity of the NaNO3 solution is (0.462 moles / 3.00 L) = approximately 0.154 M.
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