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A capillary tube of radius \( r \) is immersed in water, and water rises in it to a height \( h \). The mass of water in the capillary tube is 5 g. Another capillary tube of radius \( 2r \) is immersed in water. The mass of water that will rise in this tube is:

A. 20 g
B. 10 g
C. 5.0 g
D. 2.5 g

Answer :

Final answer:

The mass of water that will rise in the second capillary tube with radius 2r is 20g, because the volume of water in the tube, and consequently the mass, increases by a factor of four when the radius is doubled. correct option is a.

Explanation:

In the given scenario, when a capillary tube with radius r causes water to rise to height h with a mass of 5g, the volume of water in the tube can be determined using the formula for the volume of a cylinder, V = πr2h. When the radius is doubled, the new volume will be V = π(2r)2h, which is four times the original volume since the height to which the water rises is inversely proportional to the square of the radius. Thus, if the original mass is 5g, the new mass will be 4 times greater, which is 20g.

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