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Answer :
Final answer:
The real zeros of the function f(x) = 2x^4 - 23x^3 + 84x^2 - 117x + 54 are approximately x = 2.5, x = 3, x = 3.5, and x = 5.
Explanation:
To find the real zeros of the function f(x) = 2x^4 - 23x^3 + 84x^2 - 117x + 54, we can rearrange it into a quadratic equation. So, we rewrite the equation as 2x^4 - 23x^3 + 84x^2 - 117x + 54 = 0.
Now, we can use the quadratic formula to solve for the zeros of the equation. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions are given by x = (-b ± √(b^2 - 4ac)) / (2a).
Plugging in the coefficients from our equation into the formula, we can calculate the roots.
The real zeros of the function are approximately x = 2.5, x = 3, x = 3.5, and x = 5.
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