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Side A of a beaker contains 5 sodium ions and water.
Side B of the beaker contains 10 sodium ions and water.
A semi-permeable membrane, only permeable to water, divides the two sides of the beaker.

Group of answer choices:
A. Side B is hyperosmotic to Side A. Water will move by osmosis from Side B into Side A.
B. Side A is hypo-osmotic compared to Side B. Water will diffuse by osmosis from Side A into Side B.
C. Side A is hypo-osmotic compared to Side B. Water will move by osmosis from Side B into Side A.

Answer :

A semi-permeable membrane only permeable to water divides the 2 sides of the beaker is a Side A is hypo-osmotic compared to side B. Water will move by osmosis from side B into side A.

Osmosis is the movement of water through a semi-permeable membrane from an area of low solute concentration to an area of high solute concentration. In this case, side A has a lower solute concentration (5 sodium ions) than side B (10 sodium ions). Therefore, water will move by osmosis from side B into side A.

The answer choices are incorrect because:

Side B is hyperosmotic to side A. Water will move by osmosis from side B into side A. This is incorrect because side B has a higher solute concentration than side A. Water will move from an area of low solute concentration to an area of high solute concentration.

Side A is hypo-osmotic compared to side B. Water will diffuse by osmosis from side A into side B. This is incorrect because diffusion is the movement of particles from an area of high concentration to an area of low concentration. Water is not a particle, so it cannot diffuse.

For such more question on osmosis:

https://brainly.com/question/2811191

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