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An object with a height of 2.61 cm is placed 38.3 mm to the left of a lens with a focal length of 36.3 mm. Where is the image located?

Answer :

The object is located 38.3 mm to the left of the lens, and the lens has a focal length of 36.3 mm. To find the location of the image, we can use the lens formula:

1/f = 1/v - 1/u

where f is the focal length of the lens, v is the distance of the image from the lens, and u is the distance of the object from the lens.

Given that the object is 2.61 cm (or 26.1 mm) tall and is placed 38.3 mm to the left of the lens, we can calculate the distance u as:

u = -38.3 mm

Since the object is to the left of the lens, the distance u is negative.

Plugging the values into the lens formula, we have:

1/36.3 mm = 1/v - 1/-38.3 mm

Simplifying this equation, we get:

1/36.3 mm = 1/v + 1/38.3 mm

To solve for v, we can take the reciprocal of both sides:

36.3 mm = v + 38.3 mm

Subtracting 38.3 mm from both sides, we find:

v = 36.3 mm - 38.3 mm

v = -2 mm

The negative sign indicates that the image is formed on the same side as the object, which means it is a virtual image. The magnitude of the image distance is 2 mm, and since it is negative, it means the image is located 2 mm to the left of the lens.

Therefore, the image is located 2 mm to the left of the lens.

Know more about focal length here:

https://brainly.com/question/2194024

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