We appreciate your visit to You are trying to compare the Fahrenheit and Celsius scales You have two examples Temperature A is 50 degrees Celsius and 122 degrees Fahrenheit Temperature. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The graph that models the relationship between the Fahrenheit and Celsius scales is attached below.
An equation of the line in slope-intercept form
is F= 9/5 C+ 32.
I am hoping
that this answer has satisfied your query and it will be able to help you in
your endeavor, and if you would like, feel free to ask another question.
Thanks for taking the time to read You are trying to compare the Fahrenheit and Celsius scales You have two examples Temperature A is 50 degrees Celsius and 122 degrees Fahrenheit Temperature. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
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Rewritten by : Barada
For this case, the first thing we must do is define variables.
We have then:
c: temperature in degrees celsius
f: temperature in Fahrenheit
The generic equation of the line is:
[tex]f-fo = m (c-co)
[/tex]
Where, the slope is given by:
[tex]m = \frac{f2-f1}{c2-c1} [/tex]
Substituting values:
[tex]m = \frac{212-122}{100-50} [/tex]
Rewriting:
[tex]m = \frac{90}{50} [/tex]
[tex]m = \frac{9}{5} [/tex]
We choose an ordered pair:
[tex] (co, fo) = (100, 212)
[/tex] Substituting values in the generic equation:
[tex]f-212 = \frac{9}{5} (c-100)
[/tex]
Rewriting:
[tex]f-212 = \frac{9}{5}c - 180 [/tex]
[tex]f = \frac{9}{5}c - 180 + 212
[/tex]
[tex]f = \frac{9}{5}c + 32
[/tex]
Answer:
An equation of the line in slope-intercept form is:
[tex]f = \frac{9}{5}c + 32 [/tex]
See attached image.
We have then:
c: temperature in degrees celsius
f: temperature in Fahrenheit
The generic equation of the line is:
[tex]f-fo = m (c-co)
[/tex]
Where, the slope is given by:
[tex]m = \frac{f2-f1}{c2-c1} [/tex]
Substituting values:
[tex]m = \frac{212-122}{100-50} [/tex]
Rewriting:
[tex]m = \frac{90}{50} [/tex]
[tex]m = \frac{9}{5} [/tex]
We choose an ordered pair:
[tex] (co, fo) = (100, 212)
[/tex] Substituting values in the generic equation:
[tex]f-212 = \frac{9}{5} (c-100)
[/tex]
Rewriting:
[tex]f-212 = \frac{9}{5}c - 180 [/tex]
[tex]f = \frac{9}{5}c - 180 + 212
[/tex]
[tex]f = \frac{9}{5}c + 32
[/tex]
Answer:
An equation of the line in slope-intercept form is:
[tex]f = \frac{9}{5}c + 32 [/tex]
See attached image.
