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Answer :
The volume of the gas after an increase in temperature to 28.0 C is 45.69 ml
Given Data
- V1 = 35.9ml
- T1 = 22.0 Degrees
- T2 = 28.0 Degrees
We know that the expression relating volume and temperature is given as
V1/T1 = V2/T2
Substituting our given data into the expression above we have
35.9/22.0 = V2/28.0
Making V2 the subject of the formula we have
V2 = 35.9*28.0/22/0
V2 = 1005.2/22.0
V2 = 45.69 ml
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