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An enamel silver jewel has a mass of 93 kg and a volume of 10 cm³. What part of the total mass is:

i. Enamel
ii. Silver

Density of enamel is 2.5 g/cm³.
Density of silver is 10.5 g/cm³.

Answer :

The part of the total masses are:

i. 0.027%

ii. 0.113%

How to determine total mass?

To find the mass of enamel and silver in the jewel, use their respective densities and the volume of the jewel.

i. Mass of Enamel:

Density of enamel = 2.5 g/cm³

Volume of the jewel = 10 cm³

The mass of enamel can be calculated using the formula:

Mass = Density × Volume

Mass of enamel = 2.5 g/cm³ × 10 cm³ = 25 g

ii. Mass of Silver:

Density of silver = 10.5 g/cm³

Volume of the jewel = 10 cm³

The mass of silver can be calculated using the same formula:

Mass = Density × Volume

Mass of silver = 10.5 g/cm³ × 10 cm³ = 105 g

Now, to find the parts of the total mass:

i. Part of Enamel:

Mass of enamel = 25 g

Total mass of the jewel = 93 kg = 93,000 g

Part of enamel = (Mass of enamel / Total mass) × 100

Part of enamel = (25 g / 93,000 g) × 100 ≈ 0.027%

ii. Part of Silver:

Mass of silver = 105 g

Total mass of the jewel = 93 kg = 93,000 g

Part of silver = (Mass of silver / Total mass) × 100

Part of silver = (105 g / 93,000 g) × 100 ≈ 0.113%

Therefore, the enamel constitutes approximately 0.027% of the total mass, while the silver constitutes approximately 0.113% of the total mass.

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