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Answer :
Final answer:
To find the number of oxygen atoms in 6.00 grams of KClO3, we calculate the moles of KClO3 and use the mole ratio to find the moles of oxygen atoms. We then multiply this by Avogadro's number to find there are approximately 8.85 x 10^22 oxygen atoms.
Explanation:
The question is asking how many atoms of oxygen are present in 6.00 grams of potassium chlorate (KClO3). To find the number of atoms of oxygen, we first need to calculate the number of moles of KClO3 from the given mass and then use the mole ratio from the chemical formula to determine the number of moles of oxygen atoms.
We know that the molar mass of KClO3 is 122.55 g/mol, according to the periodic table and molecular weights. Therefore:
- Calculate moles of KClO3:
(6.00 g) / (122.55 g/mol) = 0.049 mol KClO3 - Since each molecule of KClO3 contains three oxygen atoms, we have:
0.049 mol KClO3 x 3 mol O / 1 mol KClO3 = 0.147 mol O - To find the total number of oxygen atoms, multiply the moles of oxygen by Avogadro's number (6.022 x 1023 atoms/mol):
0.147 mol O x 6.022 x 1023 atoms/mol ≈ 8.85 x 1022 oxygen atoms
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#SPJ11ber of moles of KClO3 from the given mass and then use the mole ratio from the chemical formula to determine the number of moles of oxygen atoms.
We know that the molar mass of KClO3 is 122.55 g/mol, according to the periodic table and molecular weights. Therefore:
Calculate moles of KClO3:
(6.00 g) / (122.55 g/mol) = 0.049 mol KClO3
Since each molecule of KClO3 contains three oxygen atoms, we have:
0.049 mol KClO3 x 3 mol O / 1 mol KClO3 = 0.147 mol O
To find the total number of oxygen atoms, multiply the moles of oxygen by Avogadro's number (6.022 x 1023 atoms/mol):
0.147 mol O x 6.022 x 1023 atoms/mol ≈ 8.85 x 1022 oxygen atoms
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