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Answer :
To find the specific heat capacity of the metal, use conservation of energy in a calorimetry experiment to set up an equation equating the heat lost by the metal to the heat gained by the water, then solve for the metal's specific heat.
The question involves calculating the specific heat capacity of a metal by using the concept of conservation of energy in a calorimetry experiment. Since no heat is lost to the surroundings in an insulated container, the heat lost by the metal will be equal to the heat gained by the water. We can use the formula q = mcΔT (where q is the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature) for both substances to set up an equation that allows us to solve for the metal's specific heat capacity.
Heat lost by metal = Heat gained by water
-mmetalcmetal(ΔTmetal) = mwatercwater(ΔTwater)
Substituting the given values:
-45.6g * cmetal * (36.3°C - 85.5°C) = 17.5g * 4.18 J/g°C * (36.3°C - 22.5°C)
Solving for cmetal gives us the specific heat capacity of the metal.
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