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One week, a construction worker bought [tex]$40 \frac{1}{10}$[/tex] pounds of nails. The next week, he bought [tex]$2 \frac{1}{2}$[/tex] times as many nails as the week before. How many pounds of nails did he buy the second week?

A. [tex]$16 \frac{1}{25}$[/tex] lb
B. [tex]$99 \frac{1}{4}$[/tex] lb
C. [tex]$80 \frac{1}{20}$[/tex] lb
D. [tex]$100 \frac{1}{4}$[/tex] lb

Answer :

Sure, let's solve this problem step-by-step:

1. First Week Purchase:
- The construction worker bought [tex]\(40 \frac{1}{10}\)[/tex] pounds of nails. This mixed number can be converted to a decimal or an improper fraction. As a decimal, [tex]\(40 \frac{1}{10}\)[/tex] is [tex]\(40.1\)[/tex] pounds.

2. Multiplier for Second Week:
- The next week, the worker bought [tex]\(2 \frac{1}{2}\)[/tex] times as many nails as the week before. This is equal to [tex]\(2.5\)[/tex] when expressed as a decimal.

3. Calculate for the Second Week:
- To find out how many pounds of nails were bought the second week, multiply the amount from the first week by the multiplier. So, we calculate:

[tex]\[
40.1 \times 2.5 = 100.25
\][/tex]

4. Conclusion:
- Therefore, the construction worker bought [tex]\(100 \frac{1}{4}\)[/tex] pounds of nails in the second week.

The correct answer is (D) [tex]\(100 \frac{1}{4} \, \text{lb}\)[/tex].

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