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Answer :
The amount of iodine-124 left after 16 days when the technician measured the original sample will be a/16.
What is an exponent?
Let a be the initial value and x be the number of days, 1/2 be the half-life factor, and y be the amount left after x days.
The exponent is given as,
[tex]\rm y = a \left ( \dfrac{1}{2} \right )^{\dfrac{x}{4}}[/tex]
Chemistry Iodine-124 has a half-life of four days. Iodine-124 sample of 40 mCi is measured by a technician.
The amount of iodine-124 left after 16 days when the technician measured the original sample will be
[tex]\rm y = a \left ( \dfrac{1}{2} \right )^{\dfrac{16}{4}}\\\\\rm y = a \left ( \dfrac{1}{2} \right )^{4}\\\\\rm y = a \left ( \dfrac{1}{16} \right )\\\\\rm y = \dfrac{a}{16}[/tex]
The amount of iodine-124 left after 16 days when the technician measured the original sample will be a/16.
More about the exponent link is given below.
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