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A 55 kg chair requires a horizontal force of 198 N to be set in motion. Once the chair is in motion, a 175 N horizontal force is exerted to keep it moving at a constant velocity.

Find the coefficients of kinetic friction ([tex] \mu_k [/tex]) and static friction ([tex] \mu_s [/tex]).

Answer :

Final answer:

The coefficient of kinetic friction (µₖ) is 0.88 and the coefficient of static friction (µₛ) is 1.

Explanation:

To find the coefficient of kinetic friction (µₖ) and static friction (µₛ), we can use the given information. The force required to set the chair in motion is the force of static friction (fₛ), which is equal to µₛN. Substituting the given values, we have:

fₛ = µₛN = µₛmg = 198 N

Now, the force required to keep the chair moving at a constant velocity is the force of kinetic friction (fₖ), which is equal to µₖN. Substituting the given values, we have:

fₖ = µₖN = µₖmg = 175 N

Dividing the equation for fₖ by the equation for fₛ gives:

µₖ/µₛ = fₖ/fₛ = (µₖmg)/(µₛmg) = 175 N / 198 N

Simplifying this equation gives:

µₖ/µₛ = 0.88

Therefore, the coefficient of kinetic friction (µₖ) is 0.88 and the coefficient of static friction (µₛ) is 1.

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