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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high?

(Formula: [tex]$PE = mgh$[/tex])

A. 75 J
B. 735 J
C. 245 J
D. 37.8 J

Answer :

To calculate the gravitational potential energy of an object at a height, we use the formula

[tex]$$
PE = m \cdot g \cdot h,
$$[/tex]

where
[tex]\( m \)[/tex] is the mass in kilograms,
[tex]\( g \)[/tex] is the gravitational acceleration (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]), and
[tex]\( h \)[/tex] is the height in meters.

Given:
[tex]\( m = 25 \, \text{kg} \)[/tex]
[tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
[tex]\( h = 3 \, \text{m} \)[/tex]

Step 1. Calculate the intermediate product [tex]\( g \cdot h \)[/tex]:

[tex]$$
g \cdot h = 9.8 \times 3 = 29.4.
$$[/tex]

Step 2. Now substitute these values into the potential energy formula:

[tex]$$
PE = 25 \cdot 29.4.
$$[/tex]

Step 3. Perform the multiplication:

[tex]$$
PE = 735 \, \text{Joules}.
$$[/tex]

Thus, the potential energy of the bicycle at the top of the hill is

[tex]$$
\boxed{735 \, \text{J}}.
$$[/tex]

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Rewritten by : Barada