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A solution is prepared using 0.125 g of glucose, [tex]C_6H_{12}O_6[/tex], in enough water to make 250 g of total solution. The concentration of this solution, expressed in parts per million, is:

A. [tex]5.00 \times 10^1[/tex] ppm
B. [tex]5.00 \times 10^2[/tex] ppm
C. [tex]5.00 \times 10^3[/tex] ppm
D. [tex]5.00 \times 10^4[/tex] ppm

Answer :

The solution is prepared using 0.125 g of glucose, C₆H₁₂O₆, in enough water to make 250 g of total solution. So, the correct option is (b) 5.00 × 10² ppm.

The concentration of this solution, expressed in parts per million (ppm), is given by the equation: ppm = (mass of solute/mass of solution) × 10^6. We are given mass of solute, glucose, and mass of solution. We are supposed to find out the concentration of the solution in ppm. We can substitute the given values and get the answer: mass of solute = 0.125 g mass of solution = 250 g ppm = (mass of solute/mass of solution) × 10⁶ = (0.125/250) × 10⁶ = 500 (Answer in part per million). Therefore, the concentration of the solution, expressed in parts per million, is 5.00 × 10² ppm.

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