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Answer :
Final answer:
Using Newton's law of gravitation and the known values of the gravitational constant, mass of Mars, and its radius, the gravitational force on a 99 kg person on Mars would be 367.29 newtons.
Explanation:
To calculate the magnitude of the gravitational force on a 99 kg person standing on the surface of Mars, we use Newton's universal law of gravitation which states that the force F between two masses m and M is proportional to the product of their masses and inversely proportional to the square of the distance r between their centers. This relationship is given by the formula:
F = GmM / r^2
where G is the gravitational constant (6.674 × 10^-11 N·m²/kg²), m is the mass of the person (99 kg), M is the mass of Mars (6.418 × 10^23 kg), and r is the radius of Mars (3.38 × 10^6 m).
The value of the acceleration due to gravity on the surface of Mars (g) can be found using the formula g = GM / r^2
Given that the value of g on Mars is 3.71 m/s²:
F = m × g
F = 99 kg × 3.71 m/s²
F = 367.29 N
Therefore, the gravitational force on a 99 kg person standing on the surface of Mars would be 367.29 newtons.
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