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Answer :
Final answer:
Assuming Raul's density to be average of the density of fresh water and seawater, we can calculate his volume as being approximately 0.0105 cubic meter.
Explanation:
Raul's ability to float in seawater but not in fresh water implies that his density is somewhere between that of seawater and fresh water. In physics, we use the concept of density, and in particular the fact that an object floats in a fluid if its density is less than the fluid's density. Density is defined as mass divided by volume. Given Raul's weight (mass), if we assume his density to be average of seawater and freshwater, we can calculate his volume.
We convert Raul's weight to mass (since weight is mass times gravity), and for simplicity we'll take G (gravity) to be 10 m/s2.
So, Raul's mass m = 235lbs / 2.2 (to convert lbs to kg) / 10 G = 10.68 kg.
The density of seawater is approximately 1025 kg/m3 and that of freshwater is about 1000 kg/m3.
Taking the average, we get a density of 1012.5 kg/m3
Knowing that density = mass/volume, we can rearrange this to find
volume = mass/density.
Inserting the numbers, we have
volume V = 10.68 kg / 1012.5 kg/m3
= 0.0105 m3.
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