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Answer :
To find the area of a triangle, when given two sides and the included angle, you can use the formula:
[tex]\text{Area} = \frac{1}{2} \times a \times b \times \sin(C)[/tex]
Let's solve each part of the question step-by-step:
1. Find the area of triangle ABC.
- Given: [tex]a = 75[/tex] cm, [tex]b = 40[/tex] cm, and [tex]C = 120^\circ[/tex].
- Use the formula:
[tex]\text{Area} = \frac{1}{2} \times 75 \times 40 \times \sin(120^\circ)[/tex]
- [tex]\sin(120^\circ)[/tex] is the same as [tex]\sin(60^\circ) = \frac{\sqrt{3}}{2}[/tex].
[tex]\text{Area} = \frac{1}{2} \times 75 \times 40 \times \frac{\sqrt{3}}{2}[/tex]
[tex]\text{Area} = 975\sqrt{3} \approx 1687.52 \text{ cm}^2[/tex]
- Rounded to three significant digits: 1680 cm²
2. Find the area of triangle ABC.
- Given: [tex]a = 40.9[/tex] cm, [tex]c = 49.1[/tex] cm, and [tex]B = 153.9^\circ[/tex].
- Use the formula:
[tex]\text{Area} = \frac{1}{2} \times 40.9 \times 49.1 \times \sin(153.9^\circ)[/tex]
- Calculate [tex]\sin(153.9^\circ)[/tex] using a calculator.
[tex]\text{Area} = \frac{1}{2} \times 40.9 \times 49.1 \times 0.4067 \approx 407.5461 \text{ cm}^2[/tex]
- Rounded to three significant digits: 408 cm²
3. Find the area of triangle ABC.
- Given: [tex]b = 0.919[/tex] cm, [tex]c = 0.671[/tex] cm, and [tex]A = 67^\circ50'[/tex].
- First, convert [tex]67^\circ50'[/tex] to decimal degrees.
[tex]67^\circ50' = 67 + \frac{50}{60} = 67.8333^\circ[/tex]
- Use the formula:
[tex]\text{Area} = \frac{1}{2} \times 0.919 \times 0.671 \times \sin(67.8333^\circ)[/tex]
- Calculate [tex]\sin(67.8333^\circ)[/tex] using a calculator.
[tex]\text{Area} \approx \frac{1}{2} \times 0.919 \times 0.671 \times 0.9272 \approx 0.28677 \text{ cm}^2[/tex]
- Rounded to three significant digits: 0.287 cm²
4. Find the area of a parallelogram.
- Given: angle [tex]60^\circ[/tex] and sides 15 inches and 13 inches.
- Use the formula for a parallelogram:
[tex]\text{Area} = \text{base} \times \text{height}[/tex]
- Here, the formula modifies to:
[tex]\text{Area} = 15 \times 13 \times \sin(60^\circ)[/tex]
- [tex]\sin(60^\circ) = \frac{\sqrt{3}}{2}[/tex]
[tex]\text{Area} = 15 \times 13 \times \frac{\sqrt{3}}{2} \approx 168.9[/tex]
- Rounded to the nearest whole number: 169
In each case, the formulas for area involve the sine of the angle, which is crucial when working with non-right triangles or other polygons.
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