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Answer :
Final answer:
After Iridium-192 emits a beta particle, the resulting isotope is Platinum-192, as the beta decay increases the atomic number by one while the mass number remains unchanged.
Explanation:
When Iridium-192 emits a beta particle, it undergoes beta decay. During beta decay, a neutron in the nucleus is converted into a proton and a beta particle (which is an electron) is emitted.
Since the mass number remains the same but the atomic number increases by one, the resulting isotope after Iridium-192 emits a beta particle is Platinum-192 (Pt-192).
This is because the atomic number of Iridium is 77, and the emission of a beta particle would increase the atomic number to 78, which is the atomic number of Platinum.
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